z^2+(2i-3)+(5-1)=0

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Solution for z^2+(2i-3)+(5-1)=0 equation:


Simplifying
z2 + (2i + -3) + (5 + -1) = 0

Reorder the terms:
z2 + (-3 + 2i) + (5 + -1) = 0

Remove parenthesis around (-3 + 2i)
z2 + -3 + 2i + (5 + -1) = 0

Combine like terms: 5 + -1 = 4
z2 + -3 + 2i + (4) = 0
z2 + -3 + 2i + 4 = 0

Reorder the terms:
-3 + 4 + 2i + z2 = 0

Combine like terms: -3 + 4 = 1
1 + 2i + z2 = 0

Solving
1 + 2i + z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 2i + -1 + z2 = 0 + -1

Reorder the terms:
1 + -1 + 2i + z2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 2i + z2 = 0 + -1
2i + z2 = 0 + -1

Combine like terms: 0 + -1 = -1
2i + z2 = -1

Add '-1z2' to each side of the equation.
2i + z2 + -1z2 = -1 + -1z2

Combine like terms: z2 + -1z2 = 0
2i + 0 = -1 + -1z2
2i = -1 + -1z2

Divide each side by '2'.
i = -0.5 + -0.5z2

Simplifying
i = -0.5 + -0.5z2

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